Question

Please answer the question.

Answer 1

Hey mate!

Here's your answer!!

bx/a + ay/b = a2 + b2 ......... eq1

x + y = 2ab .... eq 2..

frm eq 1.. b²x + a²y / ab = a² + b²

-> b²x + a²y = a³b + b³a

-> b²x - b³a = a³b - a²y

->b² ( x - ab ) = a2² ( ab - y )

-> frm eq 2 ...
b² ( x - x/2 + y/2 ) = a² ( x/2 + y/2 - y )

-> b² ( x/2 - y/2 ) = a² ( x/2 - y/2 )

-> b²x - b²y = a²x - a²y

-> x ( b² - a² ) = y ( b² - a² )

-> x = y

put the value of x in eq 2.... 2y = 2ab

$hope \: it \: helps \: you...$
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