Math, asked by shuvam1644, 5 hours ago

please answer the question​

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Answered by daisyDrishti
3

 \frac{4 +  \sqrt{5} }{4 -  \sqrt{5} }  +  \frac{4 -  \sqrt{5}}{4  +  \sqrt{5}}  \\  \\  \frac{4 +  \sqrt{5} }{4 -  \sqrt{5} }    \times  \frac{4  +  \sqrt{5} }{4 +  \sqrt{5} }  +  \frac{4 -  \sqrt{5} }{4 +  \sqrt{5} }  \times  \frac{4  +  \sqrt{5} }{4 +  \sqrt{5} }  \\  \\   \frac{( {4 +  \sqrt{5} )}^{2} }{ {4}^{2}  - ( { \sqrt{5}) }^{2} }  +  \frac{ {(4 -  \sqrt{5} )}^{2} }{ {4 -  { (\sqrt{5} )}^{2} }}  \\  \\  \frac{16 + 5 + 8 \sqrt{5} }{16 - 5}  +  \frac{16 + 5 - 8 \sqrt{5} }{16 - 5}  \\  \\  \frac{21 + 8 \sqrt{5} }{11}  +  \frac{21 - 8 \sqrt{5} }{11}  \\  \\  \frac{21 + 8 \sqrt{5}  + 21 + 8 \sqrt{5} }{11}  \\  \\  \frac{42 + 16 \sqrt{5} }{11}

hope it will help u☺️

Answered by itzsecretagent
4

Answer:-

 \sf \frac{4 +  \sqrt{5} }{4 -  \sqrt{5} }  +  \frac{4 -  \sqrt{5} }{4 +  \sqrt{5} }  \\

Rationalising the denominator

 \sf \implies\frac{4 +  \sqrt{5} }{4 -  \sqrt{5} } \times  \frac{4 +  \sqrt{5} }{4 +  \sqrt{5} }   +  \frac{4 -  \sqrt{5} }{4 +  \sqrt{5} }  \times  \frac{4 -  \sqrt{5} }{4 -  \sqrt{5} }  \\

 \sf \implies \frac{ ({4 +  \sqrt{5}) }^{2} }{ {4}^{2}  -  { \sqrt{5} }^{2} }  +  \frac{ {(4 -  \sqrt{5}) }^{2} }{ {4}^{2} -  { \sqrt{5} }^{2}  }  \\

 \sf  \implies\frac{ {(4 +  \sqrt{5}) }^{2}  +  {(4 -  \sqrt{5}) }^{2} }{ {4}^{2}  -  { \sqrt{5} }^{2} }  \\

 \sf  \implies\frac{16+5+8√5+16+5-8√5}{16 - 5}  \\

 \sf \implies \frac{21 + 21}{11}  \\

 \sf  \implies\frac{42}{11}  \\

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