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∠BAC = 40° and ∠CAS = 130°
Step-by-step explanation:
here, given: PQ ║ RS, ∠ACB = 50° and BA ⊥ RS
to find: ∠BAC and ∠CAS
now, PQ ║ RS and BA is transversal
so, ∠BAS = ∠ABC by alternate interior angles
and ∠ACB = 50°
∴∠BAC + ∠ACB + ∠ABC = 180°
= ∠BAC + 50° + 90° = 180°
= ∠BAC + 140° = 180°
= ∠BAC = 180° - 140°
= ∠BAC = 40°
∵∠BAC = 40° and ∠BAS = 90°
so, ∠CAS = ∠BAC + ∠BAS
= ∠CAS = 40° + 90°
= ∠CAS = 130°
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