Question

Please answer the question

Answer 1

Answer:

I am really sorry I don't know

Answer 2

▣ Given:-

• AB || DC
• Value of x = $\frac{4y}{3}$
• Value of y = $\frac{3z}{8}$

▣ To Find:-

• Value of ∠BCD
• Value of ∠ABC
• Value of ∠BAD

▣ Required Response:-

As, AB || DC & BD as transversal

∠DBC = ∠ADB [Alternative Interior Angles]

☞ y = 36°

• y = 36°

$→\;y = 36 \\ →\; \frac{3z}{8} = 36 \\ →\;3z = 36 \times 8 \\→\; z = \frac{\cancel{36} \times 8}{\cancel{3}} \\→\; z = 12 \times 8 \\➝ \;z = 96$

• z = 96°

By Substituting Value of "y" in Equation x

$→\; \frac{4y}{3} \\ →\; \frac{4 \times 36}{3} \\→\: 4 \times 12 \\➝\; 48$

• x = 48°

As Angle ABC = x+y

$→\;{\sf{∠ABC = 36°+48°}}$

$➝\;{\sf{∠ABC = 84°}}$

WKT

Sum of Angles in a triangle measure 180°

In ∆ABD

$→\;{\sf{∠ABD+∠BDA+∠BAD = 180°}}$

$→\;{\sf{x+36°+∠BAD = 180°}}$

$→\;{\sf{48°+36°+∠BAD = 180°}}$

$→\;{\sf{∠BAD = 180°-84°}}$

$➝\;{\sf{∠BAD = 96°}}$

• ◘ $\pink{\bold{∠BCD = 96°}}$
• ◘ $\blue{\bold{∠ABC = 84°}}$
• ◘ $\green{\bold{∠BAD = 96°}}$

$\boxed{\tt{@MrSoverign}}$

Hope It Helps You ✌️