Question

please answer the question

Answer 1

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7) we will use pythagorean theorem in this question which is.

$hypotenuse^{2} = base^{2} + height^{2}$

for the rectangle the base is 40cm and hypotenuse is 41cm

so, 

the height would be:

$hypotenuse^{2} = base^{2} + height^{2}$

$41^{2} = 40^{2} + height^{2}$

$1681 = 1600 + height^{2}$

[tex]1681 - 1600 = height^{2} [/tex]

$\sqrt{81} = height$

$height = 9cm$

we know that the perimeter of rectangle would be 2 (l + b)

so,

2(40 + 9)
2 × 49
98 cm

the perimeter of rectangle is 98 cm. 

8) we will use pythagorean theorem in this question which is.

$hypotenuse^{2} = base^{2} + height^{2}$

$hypotenuse^{2}= 5^{2} + 12^{2}$

$hypotenuse^{2} = 25 + 144$

$hypothenuse = \sqrt{169}$

$hypotenuse = 13 cm$


so, the length of ladder is 13 cm.



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