Question

please answer the question☝️​

Answer 1

Answer:

Here u=60×518=503u=60×518=503 m/s

v=15×518=256v=15×518=256 m/s

Using v2=u2+2asv2=u2+2as , we get

(503)2=(256)2+2×a×450(503)2=(256)2+2×a×450 or a=−12536×12m/s2a=-12536×12m/s2

If s1s1 is the further distance travelled before coming to rest ,

then s1=v22a=256×25×36×126×2×125s1=v22a=256×25×36×126×2×125=30 m

option c)30m