Question

please answer the question​

Answer 1

Answer:

use the formula of sintita=opposite side/hypotenuse

costita=adjacent side/hypotenuse

1)tita= 45°

sin45=AB/BC=AB/12

1/√2=AB/12

12/√2=AB

6√2cm=AB

cos45=CA/BC

1/√2=CA/12

12/√2=CA

6√2=CA

2)Tita=60

sin60=PQ/PR

1/2=PQ/10

10/2=PQ

5=PQ

cos30=QR/PR

3/√2=QR/10

30/√2=QR

15√2=QR

same as all the problems