please answer the question
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Arc AB subtends angle AOB at the centre of the circle and angle ACB equal to 35°.
We know that angle subtended by an arc at the centre of the circle is double the angle subtended by it at any point on the remaining part of the circle.
Since, angle ACB =35°
Therefore, angle AOB=2×angle ACB
»angle AOB=2×35°
»angle AOB =70°
Hope this answer helps you mate.
Please mark me as the brainliest one.
Thank you.
We know that angle subtended by an arc at the centre of the circle is double the angle subtended by it at any point on the remaining part of the circle.
Since, angle ACB =35°
Therefore, angle AOB=2×angle ACB
»angle AOB=2×35°
»angle AOB =70°
Hope this answer helps you mate.
Please mark me as the brainliest one.
Thank you.
Answered by
0
Answer:
option C is the correct answer <AOB = 70°
Step-by-step explanation
It is given that
<AOB = 35°
An angle subtended by an arc with center of the circle is double the angle subtended at any point on the remaining part of that circle.
Here, <AOB = 2 x <ACB
<AOB = 2 x 35 = 70°
Therefore <AOB = 70°
Thne the correct answer is the option C
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