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Upper part is in the shape of a trapezium. This is mirrored in the lower part as well. So area of two trapeziums added to the area of middle rectangular portion will be equal to the area of the octagon.
The Base of the triangle runs from the base of the perpendicular to the edge of the octagon. This can be calculated using Pythagorean Theorem:
Base2 = Hypotenuse2 - Perpendicular2
= 52 - 42 = 25 - 16 = 9
So, Base = 3
Hence The Upper Parallel Side of the Trapezium = 11- 6 = 5 cms (As there will be two bases of two triangles adding up to 6 cms)
Second point to note is, as it is a regular octagon so the upper parallel side = side of the octagon = 5 cms
Area of Trapezium
=12×=12× Sum of parallel sides ××Perpendicular distance
=12×11×5=52=12×11×5=52
So, Area of 2 trapeziums = 55 sq cms
Now, Area of Rectangle = Length ××Breadth
=11×5=55=11×5=55
Hence, Area of the platform =55+55=110=55+55=110 sq cms
thank you
The Base of the triangle runs from the base of the perpendicular to the edge of the octagon. This can be calculated using Pythagorean Theorem:
Base2 = Hypotenuse2 - Perpendicular2
= 52 - 42 = 25 - 16 = 9
So, Base = 3
Hence The Upper Parallel Side of the Trapezium = 11- 6 = 5 cms (As there will be two bases of two triangles adding up to 6 cms)
Second point to note is, as it is a regular octagon so the upper parallel side = side of the octagon = 5 cms
Area of Trapezium
=12×=12× Sum of parallel sides ××Perpendicular distance
=12×11×5=52=12×11×5=52
So, Area of 2 trapeziums = 55 sq cms
Now, Area of Rectangle = Length ××Breadth
=11×5=55=11×5=55
Hence, Area of the platform =55+55=110=55+55=110 sq cms
thank you
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