please answer the question.
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here we can see that the angle AOB = 120°
now we can find the area of triangle AOB = r *r *cos 60 * sin 60 = 32*32*√3/2 * 1/2 = 256√3
total area of triangle = 3*256√3 = 1330.176 cm^2
area of circle = 3.14 *32*32 = 3215.36 cm^2
area of design = 3215.36-1330.176 = 1885.18 cm^2
now you want to find the area of POQ
so we need OM and PM
just use trigonometry to find these values like
OM/ r = cos 60
PM / r = sin 60
once you get PM just double it and you will get the base and find the area
now we can find the area of triangle AOB = r *r *cos 60 * sin 60 = 32*32*√3/2 * 1/2 = 256√3
total area of triangle = 3*256√3 = 1330.176 cm^2
area of circle = 3.14 *32*32 = 3215.36 cm^2
area of design = 3215.36-1330.176 = 1885.18 cm^2
now you want to find the area of POQ
so we need OM and PM
just use trigonometry to find these values like
OM/ r = cos 60
PM / r = sin 60
once you get PM just double it and you will get the base and find the area
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bharat9291:
listen the question are different in 12.2 and tomorrow is sunday so i advice you to try them too once ,there are only 14 questions so you can do them in 1 hour
ok sir will do, thank you
they all are formula based but try them ,if you dont have time then read the questions and if you think you can do it then leave that question and if you have any problem in any question then try it
ok sir
all the best
now you should sleep ,you can study tomorrow
thank you so much sir.
you are most welcome
sir im going to sleep, i have one last doubt
ask
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