Question

Please answer the question

Answer 1

This is it.Hope it helps u.....

Answer 2

In triangle ABC and triangle CED ,
<ABC = <DEC ..........(Each of 90°)... (1)
<ACB = <DCE ..........(Common angle)... (2)
From (1) and (2) ,
Triangle CED is similar to Triangle ABC.

Hence proved .

Hope this helps! ✌