Question

please answer the question

Answer 1

which Q no. ???......

Answer 2

Step-by-step explanation:

Let the digit in ones place be x and tens place be y

Original number = 10y + x

Number formed by reversing the digits = 10x + y

Given 10y + x = 4(x + y) + 3

⇒ 10y + x − 4x − 4y = 3

⇒ 6y� − 3x� = 3

⇒ 2y� − x� = 1 → (1)

Also given that when 18 is added to the number the digits gets interchanged.

Hence (10y + x) + 18 = 10x + y

⇒ 9x − 9y = 18

⇒ x − y = 2� → (2)

Add (1) and (2), we get

2y� − x� = 1

x − y = 2

---------------

y = 3

Put y=3 in x − y = 2, we get

x − 3 = 2

∴ x = 5

Hence (10y + x) = 10(3) + 5 = 35

:)