Question

Please answer the question.

Answer 1

Answer:

$\alpha=\pm\displaystyle\frac{2}{|\vec a|}$

Perhaps you have a value for $|\vec a|$ somwhere else?

And if you are given that α is positive, then that gets rid of the "±" issue.

Hope this helps.

Step-by-step explanation:

$\displaystyle |\alpha\vec a| = |\alpha|\,|\vec a| = 2\\ \\\Rightarrow |\alpha|=\frac{2}{|\vec a|}\\ \\\Rightarrow \alpha = \pm\frac{2}{|\vec a|}$