please answer the question
Attachments:
Answers
Answered by
0
The roots are equal, so the discriminant is 0.
(b - c)^2 - (4(a - b)(c - a)) = 0
=> (b^2 - 2bc + c^2) - (4(ac - a^2 - bc + ab)) = 0
=> b^2 - 2bc + c^2 - (4ac - 4a^2 - 4bc + 4ab) = 0
=> b^2 - 2bc + c^2 - 4ac + 4a^2 + 4bc - 4ab = 0
=> 4a^2 + b^2 + c^2 - 4ab + 2bc - 4ac = 0
=> (2a - b - c)^2 = 0
=> 2a - b - c = 0
=> 2a = b + c
Hence proved!
Hope this helps. Plz mark it as the brainliest.
Plz ask me if you've any doubts.
Thank you. :-))
Similar questions