Question

please answer the question,??​

Answer 1

$surface \: area \: of \: sphere \: = surface \: area \: of \: cube \\ = > 4\pi {r}^{2} = 6 {l}^{2} \\ = > \frac{4}{6} = \frac{ {l}^{2} }{\pi {r}^{2} } \\ = > \frac{2}{3} = \frac{ {l}^{2} }{\pi {r}^{2} } \: (equation \:1) \\ from \: question \\ \frac{ ({ \frac{4}{3}\pi {r}^{3}})^{2} }{ { ({l}^{3}) }^{2} } = \frac{k}{\pi} \\ = > \frac{ \frac{16 {\pi}^{2} {r}^{6} }{9} }{ {l}^{6} } = \frac{k}{\pi} \\ = > k {l}^{6} = \frac{16 {\pi}^{3} {r}^{6} } {9} \\ = > k = \frac{16}{9} \times \frac{ {\pi}^{3} {r}^{6} }{ {l}^{6} } \\ = > k = \frac{16}{9} \times { (\frac{\pi {r}^{2} }{ {l}^{2} } })^{3} \\ = > k = \frac{16}{9} \times ({\frac{3}{2} })^{3} (from \: equation \: 1) \\ = > k = \frac{16}{9} \times \frac{27}{8} \\ = > k = 6$