Question

please answer the question ​

Answer 1

Answer

$(1+tan^2A)+(1+cot^2A)\\\\\implies sec^2A+cosec^2A\\\\\implies \dfrac{1}{cos^2A}+\dfrac{1}{sin^2A}\\\\\implies \dfrac{sin^2A+cos^2A}{sin^2Acos^2A}\\\\\implies \dfrac{1}{sin^2Acos^2A}\\\\\implies \dfrac{1}{sin^2A(1-sin^2A)}\\\\\implies \dfrac{1}{sin^2A-sin^4A}$

LHS = RHS [ Proved ]

Step-by-step explanation

Use the trigonometric identities involving squares :

1 + tan²A = sec²A

1 + cot²A = cosec²A

cos²A = 1 - sin²A

These are called the identities involving squares of the ratios of trigonometry .

Answer 2

ANSWER:------------

SOLUTION

(1+tan²A)+(1+cot²A)

sec²A+cosec²A

cos²A1+sin²A1

sin²Acos²Asin²A+cos²A

sin²Acos²A1sin²A(1−sin²A)1

sin²A−sin4A

Hence ,LHS = RHS [ Proved ]

hope it helps:--

T!—!ANKS!!!