Math, asked by SLOKESH, 11 months ago

please answer the question​

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Answers

Answered by Anonymous
0

Answer:

(secθ-tanθ)²

Step-by-step explanation:

[1/(secθ+tanθ)]²

=[( sec²θ-tan²θ)/secθ+tanθ}²                 ( sec²θ-tan²θ=1)

=[ (secθ+tanθ)(secθ-tanθ)/secθ+tanθ ]²

=(secθ-tanθ)²

=(secθ-tanθ)²


SLOKESH: sorry it is wring answer
Anonymous: what is your answer
Anonymous: what happened batayo
Anonymous: Tell what is wrong or you want to just time pass then please delete the answer.
Anonymous: I do not need marks and answer can not be wrong
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