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Angle BAC+ angle ACB =60 degree [exterior angle property ]
30 degree + angle ACB =60 degree
angle ACB= 60 degree -30 degree
angle ACB= 30 degree.
therefore z=30 degree.
z +x =180 degree [linear pair]
30degree +x =180 degree
x=180degree-30 degree
x=150 degree
again,
60 degree +y =180 degree[linear pair ]
y=180 degree -60 degree
y=120 degree
hence x =150 degree, y=120 degree ,z=30 degree
30 degree + angle ACB =60 degree
angle ACB= 60 degree -30 degree
angle ACB= 30 degree.
therefore z=30 degree.
z +x =180 degree [linear pair]
30degree +x =180 degree
x=180degree-30 degree
x=150 degree
again,
60 degree +y =180 degree[linear pair ]
y=180 degree -60 degree
y=120 degree
hence x =150 degree, y=120 degree ,z=30 degree
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here is your answer...
hope this helps you...
the value of angle x is 150° , angle y = 120° , angle z = 30°
hope this helps you...
the value of angle x is 150° , angle y = 120° , angle z = 30°
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