Question

please answer the question as fast as possible​

Answer 1

$\huge\underline{\underline{\blue{\sf{Required\:answer:-}}}}$

(a) BaCl₂ + K₂SO₄ → BaSO₄ + 2KCl

(b) 2K + 2H₂O → 2KOH + H₂

Explanation :-

(a) Barium chloride react with potassium sulphate , barium sulphate and potassium chloride are formed.

Now , Writing a chemical equation as per the given data

BaCl₂ + K₂SO₄ → BaSO₄ + KCl

Now , Balancing the chemical equation

• Amount of Ba before reaction = 1

• Amount of Cl before reaction = 2

• Amount of K before reaction = 2

• Amount of S before reaction = 1

• Amount of Oxygen before reaction = 4

Now , Observing the products part

• Amount of Ba after reaction = 1

• Amount of Cl after reaction = 1

• Amount of K after reaction = 1

• Amount of S after reaction = 1

• Amount of Oxygen after reaction = 4

Amount of K and Cl are unequal . So to make the equation balanced ,

BaCl₂ + K₂SO₄ → BaSO₄ + 2KCl

Now Amount before and after the reaction are balamced.

Hence , The required chemical reaction comes out to be ;

BaCl₂ + K₂SO₄ → BaSO₄ + 2KCl

━━━━━━━━━━━━━━━━━━━━━━━━━━

(b) Potassium metal reacts with water to give potassium hydroxide and hydrogen gas.

Now , Writing a chemical equation as per the given data

K + H₂O → KOH + H₂

Now , Balancing the chemical equation

• Amount of K before reaction = 1

• Amount of H before reaction = 2

• Amount of O before reaction = 1

Now , Observing the products part

• Amount of K after reaction = 1

• Amount of H after reaction = 1 + 2 = 3

• Amount of O after reaction = 1

Amount of Hydrogen before and after reaction are not equal . To make them equal , the reaction becomes

2K + 2H₂O → 2KOH + H₂

Now , that the amount before and after the reaction were equal.

Hence , The required balanced chemical equation comes out to be ;

2K + 2H₂O → 2KOH + H₂

Answer 2

$\bf{\blue{AnsweR :}}$

(a) BaCl₂ + K₂SO₄ → BaSO₄ + 2KCl

(b) 2K + 2H₂O → 2KOH + H₂

______________________________

$\bf{\blue{Explanation :}}$

(a) Barium chloride react with potassium sulphate , barium sulphate and potassium chloride are formed.

Now , Writing a chemical equation as per the given data

• BaCl₂ + K₂SO₄ → BaSO₄ + KCl

Now , Balancing the chemical equation

• Amount of Ba before reaction = 1

• Amount of Cl before reaction = 2

• Amount of K before reaction = 2

• Amount of S before reaction = 1

• Amount of Oxygen before reaction = 4

Now , Observing the products part

• Amount of Ba after reaction = 1

• Amount of Cl after reaction = 1

• Amount of K after reaction = 1

• Amount of S after reaction = 1

• Amount of Oxygen after reaction = 4

Amount of K and Cl are unequal . So to make the equation balanced ,

• BaCl₂ + K₂SO₄ → BaSO₄ + 2KCl

Now Amount before and after the reaction are balanced.

Hence , The required chemical reaction comes out to be ;

• BaCl₂ + K₂SO₄ → BaSO₄ + 2KCl

━━━━━━━━━━━━━━━━━━━━━━━━━━

(b) Potassium metal reacts with water to give potassium hydroxide and hydrogen gas.

Now , Writing a chemical equation as per the given data

• K + H₂O → KOH + H₂

Now , Balancing the chemical equation

• Amount of K before reaction = 1

• Amount of H before reaction = 2

• Amount of O before reaction = 1

Now , Observing the products part

• Amount of K after reaction = 1

• Amount of H after reaction = 1 + 2 = 3

• Amount of O after reaction = 1

Amount of Hydrogen before and after reaction are not equal . To make them equal , the reaction becomes

2K + 2H₂O → 2KOH + H₂

Now , that the amount before and after the reaction were equal.

Hence , The required balanced chemical equation comes out to be ;

• 2K + 2H₂O → 2KOH + H₂

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