please answer the question as fast as possible
Answers
(a) BaCl₂ + K₂SO₄ → BaSO₄ + 2KCl
(b) 2K + 2H₂O → 2KOH + H₂
Explanation :-
(a) Barium chloride react with potassium sulphate , barium sulphate and potassium chloride are formed.
Now , Writing a chemical equation as per the given data
BaCl₂ + K₂SO₄ → BaSO₄ + KCl
Now , Balancing the chemical equation
- Amount of Ba before reaction = 1
- Amount of Cl before reaction = 2
- Amount of K before reaction = 2
- Amount of S before reaction = 1
- Amount of Oxygen before reaction = 4
Now , Observing the products part
- Amount of Ba after reaction = 1
- Amount of Cl after reaction = 1
- Amount of K after reaction = 1
- Amount of S after reaction = 1
- Amount of Oxygen after reaction = 4
Amount of K and Cl are unequal . So to make the equation balanced ,
BaCl₂ + K₂SO₄ → BaSO₄ + 2KCl
Now Amount before and after the reaction are balamced.
Hence , The required chemical reaction comes out to be ;
BaCl₂ + K₂SO₄ → BaSO₄ + 2KCl
━━━━━━━━━━━━━━━━━━━━━━━━━━
(b) Potassium metal reacts with water to give potassium hydroxide and hydrogen gas.
Now , Writing a chemical equation as per the given data
K + H₂O → KOH + H₂
Now , Balancing the chemical equation
- Amount of K before reaction = 1
- Amount of H before reaction = 2
- Amount of O before reaction = 1
Now , Observing the products part
- Amount of K after reaction = 1
- Amount of H after reaction = 1 + 2 = 3
- Amount of O after reaction = 1
Amount of Hydrogen before and after reaction are not equal . To make them equal , the reaction becomes
2K + 2H₂O → 2KOH + H₂
Now , that the amount before and after the reaction were equal.
Hence , The required balanced chemical equation comes out to be ;
2K + 2H₂O → 2KOH + H₂
(a) BaCl₂ + K₂SO₄ → BaSO₄ + 2KCl
(b) 2K + 2H₂O → 2KOH + H₂
______________________________
(a) Barium chloride react with potassium sulphate , barium sulphate and potassium chloride are formed.
Now , Writing a chemical equation as per the given data
- BaCl₂ + K₂SO₄ → BaSO₄ + KCl
Now , Balancing the chemical equation
- Amount of Ba before reaction = 1
- Amount of Cl before reaction = 2
- Amount of K before reaction = 2
- Amount of S before reaction = 1
- Amount of Oxygen before reaction = 4
Now , Observing the products part
- Amount of Ba after reaction = 1
- Amount of Cl after reaction = 1
- Amount of K after reaction = 1
- Amount of S after reaction = 1
- Amount of Oxygen after reaction = 4
Amount of K and Cl are unequal . So to make the equation balanced ,
- BaCl₂ + K₂SO₄ → BaSO₄ + 2KCl
Now Amount before and after the reaction are balanced.
Hence , The required chemical reaction comes out to be ;
- BaCl₂ + K₂SO₄ → BaSO₄ + 2KCl
━━━━━━━━━━━━━━━━━━━━━━━━━━
(b) Potassium metal reacts with water to give potassium hydroxide and hydrogen gas.
Now , Writing a chemical equation as per the given data
- K + H₂O → KOH + H₂
Now , Balancing the chemical equation
- Amount of K before reaction = 1
- Amount of H before reaction = 2
- Amount of O before reaction = 1
Now , Observing the products part
- Amount of K after reaction = 1
- Amount of H after reaction = 1 + 2 = 3
- Amount of O after reaction = 1
Amount of Hydrogen before and after reaction are not equal . To make them equal , the reaction becomes
2K + 2H₂O → 2KOH + H₂
Now , that the amount before and after the reaction were equal.
Hence , The required balanced chemical equation comes out to be ;
- 2K + 2H₂O → 2KOH + H₂