CBSE BOARD X, asked by AksharaKerala, 8 months ago

Please answer the question as fast as possible and please do not give any wrong​

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Answered by archan4
2

Answer:

960 days

Explanation:

8men 12 boy take 10 days

1men 12 boy take 10×12 days

1 men 1 boy take 10×12×8 days

= 960 days

keeping point that as the men or boys are reducing the days are increasing.

Hope my answer is helpful to you if, then please mark me brainliest.

Answered by zaina1234
1

Answer:

Hope it helps u!... If yes mark me as BRAINLIEST... Ans is down

Explanation:

Let the time taken by man be x days

time taken by boys be y days

work done by 1 man in one day=1/x

work done by 1 boy in one day=1/y

8/x+12/y = 1/10............eq 1

6/x+ 8/y = 1/14..........eq2

Let u=1/x & v=1/y

8u+ 12y=1/10.........eq3

6u+8v= 1/14...........eq4

Multiplying eq3 by 2 & eq4 by 3

16u+ 24y=2/10.........eq5

18u+24v= 3/14.........eq6

subtract eq 5 & 6

-2u= -3/14+2/10

-2u = (-3×10 +2×14)/140

-2u=( -30+28)/140

-2u=-2/140

u=1/140

put this value in eq 5

16u+ 24y=2/10

16×1/140 +24y =1/5

4/35+24y= 1/5

24y= 1/5-4/35

24y= (1×7 -4)/35

24y = (7-4)/35

24y= 3/35

y= 3/35×24

y= 1/280

u=1/x

1/140 = 1/x

x=140

v=1/y

1/280 = 1/y

y=280

A man complete the work in 140 days

A boy can complete the work in 280 days

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