Question

Please answer the question as soon as possible​

Answer 1

Answer:

$[ (2x^2+3xy-5) + (7+2xy-x^2)] - [3xy+x^2-2]\\2x^2 + 3xy - 5 + 7+2xy-x^2 - ( 3xy+x^2-2)\\x^2 + 5xy + 2 - (3xy+x^2-2)\\x^2 +5xy+2 - 3xy - x^2 + 2\\2xy + 4\\2(xy + 2)$

Answer 2

Answer:

2xy+4

Step-by-step explanation:

2x²+3xy-5-x²+2xy+7= 2x²-x²+3xy+2xy-5+7

= x²+5xy+2

x²+5xy+2-(x²+3xy-2)=x²+5xy+2-x²-3xy+2

=2xy+4