Math, asked by intelligent83, 5 months ago

please answer the question ASAP


In the given figure, ABCD is a trapezium in which
AD = 13 cm, BC = 5 cm, CD = 17 cm and
ZA = B = 90°
Calculate : (i) AB (ii) Area of trap. ABCD.​

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Answers

Answered by muthushree
1

Answer:

1. AB = 15cm, 2)Area of trapezium = 135\ cm^2135 cm

2

Step-by-step explanation:

Given,AD = 13cm,BC = 5cm, CD = 17cm ,∠A =∠B =90°

Construction:

Draw a trapezium ABCD such that DE perpendicular to BC which is parallel to AB.

Since,BC = BE + EC

13cm = 5cm + 8 cm

Also,AD = 5cm

Since ∠A = ∠B = 90°

⇒AD ║ BC.

Now,In ΔDEC

∠DEC = 90°

By applyimg Pythagoras Theorem

DC^2 = DE^2 + EC^2DC

2

=DE

2

+EC

2

(17)^2 = (DE)^2 + (8)^2(17)

2

=(DE)

2

+(8)

2

289 = (DE)^2 + 64289=(DE)

2

+64

(DE)^2 = 289 - 64(DE)

2

=289−64

= 225

DE = 15cm

Also,AB = 15cm (Since AB is parallel and equal to DE)

In trapezium ABCD

AB is the height of trapezium parallel to BC.

Now,

Area of trapezium = \frac{1}{2}\times (\textrm{sum of opposite parallel sides})\times\textrm{height}

2

1

×(sum of opposite parallel sides)×height

= \frac{1}{2}\times (13cm + 5cm)\times 15cm

2

1

×(13cm+5cm)×15cm

= \frac{1}{2}\times (18cm)\times 15cm

2

1

×(18cm)×15cm

= 135\ cm^2135 cm

2

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