Question

Please answer the question attached.​

Answer 1

Hi dude.

Here is your answer

We are given that

Copper + Nitric Acid -> Copper Oxide

2.16 g of copper + Nitric Acid -> 2.70 g of copper Oxide.

Hence

by law of conservation of mass

Mass is Nitric Acid = 2.70 - 2.16 = 0.54 g

Ratio of copper : Nitric Acid

=> 2.16 : 0.54

=> 4 : 1

In second case,

1.15 g of copper Oxide = 0.92 g of copper + Nitric Acid

By law of conservation of mass (mass of reactants = mass of products)

mass of Nitric Acid = 1.15 - 0.92 = 0.23 g

Ratio of copper : Nitric Acid

=> 0.92 : 0.23

=> 4:1

Since in both cases, copper paired with Nitric acid in a fixed ratio by mass of 4 : 1,

Hence these results are in accordance with the law of constant proportions.

Hope this helps

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