Question

please answer the question attached please help. please answer fast it's very urgent

Answer 1

Answer:

HERE IS THE ANSWER

Step-by-step explanation:

here it is given that AB=BD and AC=CD

AND also BC is common side in both the triangles

and keeping this in mind when we join both triangles we get a parralelogram

we know that a parralelogram whose all side are equal is a rhombus

now coming back

in ΔABC and ΔDBC

AB=CD (GIVEN)

AC=BD (GIVEN)

BC=BC (COMMON and GIVEN)

SO ΔABC≅ΔDBC

∠ABD=∠ACD because as stated in theorem that the opposite angles of a parallelogram are equal ∵∠ABD=∠ACD