please answer the question below
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Answer:
angle SQT is 90°
Hope you got it
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Step-by-step explanation:
In ∆RPT,
<PRT + <RPT + <RTP = 180°
50° + 100° + <RTP = 180°
150° + <RTP = 180°
<RTP = 180° - 150°
---••• <RTP = 30°
---••• <RTP = <STQ = 30° ( Vertically Opposite Angles are equal)
In ∆SQT,
<QST + <SQT + <STQ = 180°
60° + <SQT + 30° = 180°
90° + <SQT = 180°
<SQT = 180° - 90°
---••• <SQT = 90°
Therefore, <SQT = 90°
I hope this helps you!
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