Please answer the question below
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please support me question is right
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Given: l is bisector of ∠A.and ∠P=∠Q=90°
To prove: 1. ΔAPB≅ΔAQB 2.BP=BQ
Proof:
1. ∠BAP=∠BAQ (l is bisector) (given)
AB=AB (common)
∠P=∠Q (each 90°) (given)
Therefore, ΔAPB≅ΔAQB
2. ΔAPB≅ΔAQB (proved above)
so BP=BQ (by cpct)
//Hope you understood, and sorry if i am wrong...//
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