Math, asked by gloria1975sanga, 20 days ago

please answer the question chapter is exponents and power​

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Answered by Salmonpanna2022
3

Step-by-step explanation:

  \rm\underline{ Solution-} \\

Given expression,

\rm(2^{-1}-3^{-1})^{-1}+(6^{-1}-8^{-1})^{-1} \\

Calculate 2 to the power -1 and get 1/2.

\longrightarrow\rm \bigg( \frac{1}{2}-3^{-1}\bigg)^{-1}+(6^{-1}-8^{-1})^{-1} \\

Calculate 3 to the power -1 and get 1/3.

\longrightarrow\rm \bigg( \frac{1}{2}- \frac{1}{3} \bigg)^{-1}+(6^{-1}-8^{-1})^{-1} \\

Subtract 1/3 from 1/2 to get 1/6.

\longrightarrow\rm \bigg(  \frac{1}{6} \bigg)^{-1}+(6^{-1}-8^{-1})^{-1} \\

Calculate 1/6 to the power -1 and get 6.

\longrightarrow\rm6+(6^{-1}-8^{-1})^{-1} \\

Calculate 6 to the power of -1 and get 1/6.

\longrightarrow\rm6+ \bigg( \frac{1}{6} -8^{-1} \bigg)^{-1} \\

Calculate 8 to the power -1 and get 1/8.

\longrightarrow\rm6+ \bigg( \frac{1}{6} - \frac{1}{8}  \bigg)^{-1} \\

Subtract 1/8 from 1/6 and get 1/24.

\longrightarrow\rm6+ \bigg(  \frac{1}{24} \bigg)^{-1} \\

Calculate 1/24 to the power -1 and get 24.

\longrightarrow\rm6+ 24 \\

Add 6 and 24 to get 30.

\longrightarrow\rm30 \\

Hence, 30 is your required ans.

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