Math, asked by kavya82008, 1 month ago

Please answer the question correctly.​

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Answered by BangtansLifePartner
11

(xp/xq)^p+q

(xq/xr)^q+r

(xr/xp)^r-p

= (xp-q)^p+q

= (xq-r)^q+r

=(xr+p)r+p

=(x)^p2-q2

=(x)^q2-r2

=(x)^r2-p2

=(x)p2-q2+q2-r2+r2-p2

=(x)0

=1

Answered by Kokkiearmy
4

Answer:

( \frac{xp}{xq} )p + q \\  (\frac{xq}{xr} )q + r \\ ( \frac{xr}{xp} )r + p \\  = (xp - q)p + q \\ (xq - r)r + p

 = (x)p2 - q2 \\ (x)q2 - r2 \\ (x)r2 - p2 \\  = (x)p2 - q2 + q2 - r2 + r2 - p2 \\

 = (x)0 \\  = 1

Your answer is 1 .

Hope it will help you

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