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Answers
Answer: given , (s)depth of well = 44.1 m
Time for splash heard after hitting the stone
t( sound heard) = 0.13 s
Velocity of sound in air = ?
u (initial velocity) of stone = 0 m/s
a (acceleration) of earth = 9.8m/s²
By using second equation if motion, we can find how much time take by stone to travel in air,
s=ut+(1/2)at²
44.1m = 0 (t)+ 1/2 × 9.8 m/s²×t²
44.1m = 4.9m/s²×t²
t² = 44.1m÷4.9m/s²
t² = 9 s⁻²
t = √9 s⁻²
t(air) = 3 s( second)
For reflected sound wave:
v ( velocity) = s (distance)/ total time
v = 44.1 m / t¹-t(air)
v = 44.1 m / 0.13-3 s
v = 336.23076 m/s
( I used calculator here )
Hence ,
velocity of sound in air = 336.23076 m/s
So according to option it is closed to
(2) 339 m/s
Hope u like
it is your answer u can use this method to find velocity of sound in air for other questions too
Thanks