Question

Please answer the question correctly, friends.

x(y-z)+y(z-x)+z(x-y)​

Answer 1

Answer:

It's 0 or 1

Step-by-step explanation:

xy-xz+zy-xy+xz-yz

xy negative xy se cancel ho gya

xz negative xz se cancel ho gya

yz negative yz se cancel ho gya

Answer 2

Answer:

0

Step-by-step explanation:

$x(y - z) + y(z - x) + z(x - y) \\ = xy - zx + yz - xy + zx - yz \\ = 0$