Math, asked by vijaykumar26101982, 7 hours ago

please answer the question dont write anything else. whos gonna give the answer im gonna mark u as brainlist.​

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Answered by thealonewalker1678
1

Answer:

a.\frac{3}{26}

b.\frac{1}{26}

c.\frac{1}{52}

d.\frac{1}{26}

Step-by-step explanation:

a. Total number of cards = 52.

So, the number of possible outcomes = 52

Let, E be the event of getting a black face card

There will be a total of 6 black face cards.

Number of favourable outcomes = 6

P(E)= No. of possible outcomes / No. of favourable outcomes

P(E)= \frac{6}{52} = \frac{3}{26}

Hence the probability of getting a black face card is \frac{3}{26}.

b. Total number of cards = 52.

So, the number of possible outcomes = 52

Let, E be the event of getting a red jack

There will be a total of 2 red jack card.

Number of favourable outcomes = 2

P(E)= No. of possible outcomes / No. of favourable outcomes

P(E)= \frac{2}{52} = \frac{1}{26}

Hence the probability of getting a black face card is \frac{1}{26}.

c. Total number of cards = 52.

So, the number of possible outcomes = 52

Let, E be the event of getting a 4 of spade

There will be a total of '1' 4 of spades.

Number of favourable outcomes = 1

P(E)= No. of possible outcomes / No. of favourable outcomes

P(E)= \frac{1}{52}  

Hence the probability of getting a black face card is \frac{1}{52}.

d. Total number of cards = 52.

So, the number of possible outcomes = 52

Let, E be the event of getting a red ace

There will be a total of 2 red ace cards.

Number of favourable outcomes = 2

P(E)= No. of possible outcomes / No. of favourable outcomes

P(E)= \frac{2}{52} = \frac{1}{26}

Hence the probability of getting a black face card is \frac{1}{26}.

HOPE IT HELPS.

THANK YOU.

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