Question

Please answer the question fast​

Answer 1

Answer:

a option

Step-by-step explanation:

hope you get your answer

Answer 2

Answer:

$\green{\therefore \bigg( {2x}^{2} + \frac{1}{3 {x}^{2} } \bigg)^{2} = {4x}^{4} + \frac{1}{9 {x}^{4} } + \frac{4}{3}}$

Step-by-step explanation:

$\to \bigg( {2x}^{2} + \frac{1}{3 {x}^{2} } \bigg)^{2} \\ \\ \bold{ {(a + b)}^{2} = {a}^{2} + {b}^{2} + 2ab} \\ \\ \to ( {2x}^{2} )^{2} + \bigg(\frac{1}{3 {x}^{2} } \bigg) ^{2} + 2 \times {2x}^{2} \times \frac{1}{3 {x}^{2} } \\ \\ \to 4 {x}^{4} + \frac{1}{9 { x }^{4} } + \frac{4}{3} \\ \\ \green{\therefore \bigg( {2x}^{2} + \frac{1}{3 {x}^{2} } \bigg)^{2} = {4x}^{4} + \frac{1}{9 {x}^{4} } + \frac{4}{3}}$