Question

please answer the question fast​

Answer 1

Given:

• 0 is the center of the circle

To find:

• Find the x

Solution:

• Since , Angle subtented by arc on circle are equal
• Thus, we get ,∠ABC = ∠BDC
• Therefore, ∠BDC= 35
• Consider triangle BDC
• ∠DBC+∠CBD+∠BCD = 180°[Sum of angle of triangle is 180°]

$On \: Solving \: We \: Get \\ 65° + x + 35° = 180° \\ x = 180° - 100° \\ x = 80°$

$\colorbox{cyan}{Hope \: it \: Helps \: uh!...}$

Answer 2

Solution :-

we know that, angle subtends by same chord on the circumference of the circle are equal .

from image we can see that, chord CB, subtends ∠CAB and ∠CDB at the circumference .

So,

→ ∠CDB = ∠CAB = 35°

now, in ∆CDB we have,

→ ∠CDB = 35°

→ ∠CBD = 65° (given)

then,

→ ∠CDB + ∠CBD + ∠DCB = 180° (By angle sum Property of a ∆.)

→ 35° + 65° + x° = 180°

→ 100° + x° = 180°

→ x° = 180° - 100°

→ x° = 80° (Ans.)

Hence, value of ∠x is 80° .

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