Question

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Answer 1

Answer:

L.H.S = sin6a+cos6a+3sin2acos2a

= sin6a+cos6a+3sin2acos2a(sin2a+cos2a)

Since,

(sin2a+cos2a) = 1

=(sin2a)3(cos2a)3+3sin2acos2a(sin2a+cos2a)

= (sin2a+cos2a)3

Since; a3+b3+3ab(a+b)

= (a+b)3

= 13= 1= R.H. S

Hence proved.

Step-by-step explanation:

hope it helps......