Math, asked by sandeepcharlie1, 9 months ago

Please answer the question from the attachment

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Answered by pk2varma
0

Answer:

 {3}^{x}  +  {3}^{ - x}  - 2 = 0 \\  {3}^{x}  = y \\ y + 1 \div y - 2 = 0 \\  {y}^{2}  - 2y + 1 = 0 \\ y = 1 \\  {3}^{x}  = 1 \\ x = 0

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