please answer the question given below
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the highest number between remaining 2 will be any number between 20 and 71 we can assume any combination
as (a+b+c)/3=30
so a+b+c= 90
19+b+c=90
b+c= 90-19
as (a+b+c)/3=30
so a+b+c= 90
19+b+c=90
b+c= 90-19
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