Please answer the question given in attachment with explanation.
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gaurav2013c:
C is correct but i need explanation
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Heya @User
here, answer is option (c)
explanation :-
( n ) = ultimate
(n- 1 ) = penultimate
( n-2) = Anti -penutimate
The group of elements in which the differentiating electrons enter the anti-penultimate shell of atoms are called F-block elements
=max capacity of F orbitals is 14,
so given there 1-14
*sub-shells being filled up in each period
1st period = 1s
2nd period = 2s 2p
3rd period = 3s 3p
4th period = 4s 3d 4p
5th period =5s 4d 5p
6th period =6s 4f 5d 6p
7th period = 7s 5f 6d 7p
so, the option c satisfies this order
means, when n=6 .ie, 6th period-
so value of f= (n-2) =4f
value of d = (n-1) = 5d
f-block elements always end with full filled s-orbital
_________________________
@_@Mavis:)
here, answer is option (c)
explanation :-
( n ) = ultimate
(n- 1 ) = penultimate
( n-2) = Anti -penutimate
The group of elements in which the differentiating electrons enter the anti-penultimate shell of atoms are called F-block elements
=max capacity of F orbitals is 14,
so given there 1-14
*sub-shells being filled up in each period
1st period = 1s
2nd period = 2s 2p
3rd period = 3s 3p
4th period = 4s 3d 4p
5th period =5s 4d 5p
6th period =6s 4f 5d 6p
7th period = 7s 5f 6d 7p
so, the option c satisfies this order
means, when n=6 .ie, 6th period-
so value of f= (n-2) =4f
value of d = (n-1) = 5d
f-block elements always end with full filled s-orbital
_________________________
@_@Mavis:)
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