Question

please answer the question given in the attachment
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Answer 1

Answer:

Given that E°cell = 0.16v

E°cell = (0.059/n) log Kc

Therefore, log Kc = (E°cell × n)/0.059 here. n = 4

log Kc = (0.16 × 4)/0.059

log Kc = 10.8

Kc = antilog 10.8

Kc = 6.31 × 10^10

so the value of equilibrium constant is 6.31 × 10^10

Hope this will help you dear

Answer 2

Answer:

hope this helps you answer given in the attachment

reffer attachment

thank you