please answer the question given in the photograph
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Let v be the velocity of the boy on the cart as the cart starts moving
The total momenta of the boy and cart before the interaction
= 40 kg *5 m/s +3 kg *0 m/s
=200 kg m/s
The total momenta after the interaction
= (40+3)kg * v m/s
= 43 v kg m/s
According to the law of conservation of momentum the total momentum is conserved during the interaction
That is ,
43v=200
=>v=200/43=+4.65m/s
The boy on cart would move with a velocity of 4.65 m/s in the direction in which the boy jumped
Hope it may help you
Note-the sign * means the multiplying symbol .
The total momenta of the boy and cart before the interaction
= 40 kg *5 m/s +3 kg *0 m/s
=200 kg m/s
The total momenta after the interaction
= (40+3)kg * v m/s
= 43 v kg m/s
According to the law of conservation of momentum the total momentum is conserved during the interaction
That is ,
43v=200
=>v=200/43=+4.65m/s
The boy on cart would move with a velocity of 4.65 m/s in the direction in which the boy jumped
Hope it may help you
Note-the sign * means the multiplying symbol .
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1
Answer: can't understand question ..
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