please answer the question given in the picture . step by step explanation please.....
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Answer:
In Parallelogram AQCP----
Step-by-step explanation:
anglePAB = angleQCD. (( By alternate Interior angle ))
In ∆PAB & ∆QCD----
PA=QC. ((oppo. side of || gm))
AB=CD. ((oppo. side of ||gm ))
Angle PAB = Angle QCD
By SAS Cong. crit. ∆PAB Congruent to ∆QCD....
PB=QD. ((( By CPCT. )))
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