Question

please answer the question guys

Answer 1

It is given that,

∠P=60°

then, let

∠Q= 2x

∠R= 3x

∠S= 7x

We know that the Sum of all the angle of a quadrilateral = 360°

A/Q,

⇒∠P+∠Q+∠R+∠S = 360°

⇒60°+2x+3x+7x = 360°

⇒ 2x+3x+7x = 360°-60°

⇒ 12x = 300°

⇒ x = 300°/12

∴ x = 25°

Now,

∠P = 60°

∠Q = 2x = 2 x 25° = 50°

∠R = 3x = 3 x 25° = 75°

∠S = 7x = 7 x 25° = 175°

HENCE, the measure of ∠S = 175°

Verification

∠P+∠Q+∠R+∠S = 360°

⇒ 60°+50°+75°+175°=360°

∴ 360°=360°

HENCE, L.H.S=R.H.S

Verified

Answer 2

hey friend
here your answer
60+2x+ 3x+7x = 360°
12x=360°-60°
12x= 300
x = 25°
then, angle Q = 2x= 2×25= 50°
angle R= 3x = 3×25° =75°
angle S = 7x = 7× 25° = 175 °

finally this is ryt answer