please answer the question I want reason
Attachments:
Answers
Answered by
2
here spring is in equilibrium and also mass of spring didn't mention it means spring is light or neglible mass
for first spring which is connected in block
in equilibrium condition
spring force = mg
F1 = mg
hence first read 4 kg-wt
now for second spring
F2 = F1
but from above F1 = mg
so, F2 = mg = 4g
so , reading of second spring = 4 kg-wt
so , both read same mass e.g 4kg
for first spring which is connected in block
in equilibrium condition
spring force = mg
F1 = mg
hence first read 4 kg-wt
now for second spring
F2 = F1
but from above F1 = mg
so, F2 = mg = 4g
so , reading of second spring = 4 kg-wt
so , both read same mass e.g 4kg
abhi178:
equilibrium means no motion ,
net force = 0
upward force = downward force
if mass is not mentioned should we consider the mass as negligible??
if mass is not mentioned should we consider the mass as negligible?? I
if mass is not mentioned should we consider the mass as negligible?? I
if mass is not mentioned should we consider the mass as negligible??
yes sure
in motion mass given then you consider mass of pulley , spring , string etc
oh thanks
Answered by
0
Answer:
here spring is in equilibrium and also mass of spring didn't mention it means spring is light or negligible mass
for first spring which is connected in
block in equilibrium condition
spring force = = mg F1 = mg hence first read 4 kg-wt
now for second spring F2 = F1
but from above F1 = mg
so, F2 = mg = 4g
so , reading of second spring = 4 kg-wt
so , both read same mass e.g 4kg
Similar questions