Physics, asked by john44, 1 year ago

please answer the question I want reason

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Answered by abhi178

here spring is in equilibrium and also mass of spring didn't mention it means spring is light or neglible mass

for first spring which is connected in block
in equilibrium condition

spring force = mg
F1 = mg
hence first read 4 kg-wt

now for second spring
F2 = F1
but from above F1 = mg
so, F2 = mg = 4g
so , reading of second spring = 4 kg-wt

so , both read same mass e.g 4kg

abhi178: equilibrium means no motion ,

abhi178: net force = 0

abhi178: upward force = downward force

john44: if mass is not mentioned should we consider the mass as negligible??

john44: if mass is not mentioned should we consider the mass as negligible?? I

john44: if mass is not mentioned should we consider the mass as negligible??

abhi178: yes sure

abhi178: in motion mass given then you consider mass of pulley , spring , string etc

john44: oh thanks

Answered by erajireddy6

Answer:

here spring is in equilibrium and also mass of spring didn't mention it means spring is light or negligible mass

for first spring which is connected in

block in equilibrium condition

spring force = = mg F1 = mg hence first read 4 kg-wt

now for second spring F2 = F1

but from above F1 = mg

so, F2 = mg = 4g

so , reading of second spring = 4 kg-wt

so , both read same mass e.g 4kg

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