Question

please answer the question I will make your answer the brainliest answer please ​

Answer 1

Answer:

Hello

Step-by-step explanation:

In ΔBED and ΔBCA by AA similarity

ΔBED ≈ ΔBCA so we get,  (Triangles are similar)

$\frac{BE}{BC} = \frac{BD}{BA} = \frac{x}{y}$

Now,

$\frac{a}{a+b} = \frac{x}{y}$

On cross multiplying we get,

$x = \frac{ay}{a+b}$

∴ C is your answer..... Hope this helps