Math, asked by Itzheartcracer, 3 days ago

Please answer the question in attachment

Attachments:

Answers

Answered by mathdude500
26

\large\underline{\sf{Solution-}}

Given curve is

\rm :\longmapsto\:f(x) =  {x}^{3} -  {x}^{2} - x -  \dfrac{11}{4}

Further, it is given that k is a constant real number such that f(x) = k has three real solutions.

Now, we have to find the real value of k, using graphical Method.

If we draw a line y = 2, it cuts the graph of f(x) in one distinct point.

If we draw a line y = 0, it cuts the graph of f(x) in one distinct point.

If we draw a line y = - 2, it cuts the graph of f(x) in one distinct point.

If we draw a line y = - 3, it cuts the graph of f(x) in three distinct points.

Hence, k = - 3, so that f(x) = k has three real solutions.

  • So, option (d) is correct

Attachments:
Answered by XxitsmrseenuxX
4

Answer:

\large\underline{\sf{Solution-}}

Given curve is

\rm :\longmapsto\:f(x) =  {x}^{3} -  {x}^{2} - x -  \dfrac{11}{4}

Further, it is given that k is a constant real number such that f(x) = k has three real solutions.

Now, we have to find the real value of k, using graphical Method.

If we draw a line y = 2, it cuts the graph of f(x) in one distinct point.

If we draw a line y = 0, it cuts the graph of f(x) in one distinct point.

If we draw a line y = - 2, it cuts the graph of f(x) in one distinct point.

If we draw a line y = - 3, it cuts the graph of f(x) in three distinct points.

Hence, k = - 3, so that f(x) = k has three real solutions.

So, option (d) is correct

Attachments:
Similar questions