please answer the question in attachment
and yes it is from neet
Answers
Answer:
(b) For n =1 the electron has a more negative energy etc
Step-by-step explanation:
To completely understand the concepts we need to go through each of the options carefully
(a) Equation can be used to calculate the change in energy when the electron changes orbit
True; this change in energy can be found out by the difference of energy value of the orbit from which the electron and the energy value of the orbit to which the electron has made the transition
(B) For n = 1 the electron has more negative energy etc
False; because
1) First we need to understand that the equation given to us give us the total energy of an electron.
2) At infinite distance from the nucleus, that is n = infinite, the potential energy becomes zero because the equation is divided by n² , and dividing anything by infinite will give you zero.
3) With Potential energy at n = infinite zero being set as a benchmark, all the values of n less than infinite will have a -ve sign.
4) Now more -ve the value of potential energy is, more closer it is to the nucleus, hence more tightly it will be bound in that orbit.
Hence electron at n = 1 is more tightly bound than the electron a n = 6
(c) True;
The energy at infinite distance is taken as zero, hence the potential energy of electron near the nucleus will be less than zero
(d) True,
Larger the value of n, farther is the electron away from the nucleus, hence larger is the radius
-Do not confuse the 'n' in this question with principal quantum number
-To understand the -ve sign convention of potential energy we can relate it to the gravitational potential energy; which is zero at the surface of the earth [The benchmark], it is +ve above height h and it is -ve below height h from the surface
Answer:
Hi Aryan kaisa hai
Step-by-step explanation:
please answer the question in attachment
and yes it is from neet
