Please answer the question in attachment... I will give brainliest
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hello friend
here you go
cos a= adjacent/hypotenuse= 1/2
therefore adjacent= 1cm
hypotenuse= 2cm
now find the third side(opposite side) by pythagoras theorem
2²=1²+x²
4=1+x²
x=√3 cm
third side = √3 cm
tan a= opposite/adjacent=√3/1=√3
sin b= opposite/hypotenuse= 1/√2
therefore
opposite= 1 cm
hypotenuse= √2 cm
now lets find the tird side( adjacent side) by pythagoras theorem
√2²=1²+y²
2=1+y²
y=√1=1
third side= 1
tan b= opposite / adjacent= 1/1=1 cm
now lets solve by putting values of tan a and tan b
(tan a- tan b)/( 1+tana+tanb)
=(√3-1)/(1+√3+1)
=(√3-1)/(2+√3)
if u rationalise the denominator u will get
3√3-5
plz mark as brainliest
if u have any doubt ask in the comments session
here you go
cos a= adjacent/hypotenuse= 1/2
therefore adjacent= 1cm
hypotenuse= 2cm
now find the third side(opposite side) by pythagoras theorem
2²=1²+x²
4=1+x²
x=√3 cm
third side = √3 cm
tan a= opposite/adjacent=√3/1=√3
sin b= opposite/hypotenuse= 1/√2
therefore
opposite= 1 cm
hypotenuse= √2 cm
now lets find the tird side( adjacent side) by pythagoras theorem
√2²=1²+y²
2=1+y²
y=√1=1
third side= 1
tan b= opposite / adjacent= 1/1=1 cm
now lets solve by putting values of tan a and tan b
(tan a- tan b)/( 1+tana+tanb)
=(√3-1)/(1+√3+1)
=(√3-1)/(2+√3)
if u rationalise the denominator u will get
3√3-5
plz mark as brainliest
if u have any doubt ask in the comments session
Anonymous:
PLZ MARK AS BRAINLIEST
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