Question

please answer the question in the attachment.

Wrong answer will be reported​

Answer 1

Answer:

Please refer the attachment dear

Answer 2

Answer:

Let the average speed of the passenger train be 'x' km/hr and the average speed of the express train be (x + 11) km/hr

Distance between Mysore and Bangalore = 132 km

It is given that the time taken by the express train to cover the distance of 132 km is 1 hour less than the passenger train to cover the same distance.

So, time taken by passenger train = 132/x hr

The time taken by the express train = {(132)/x+11} hr

Now, according to the question

{132/(x+11)} = 132/x + 1

After taking L.C.M. of 132/x +1 and then solving it we get (132+x)/x.

Now,

{132/(x+11)} = (132+x)/x

By cross multiplying, we get

132x = x²+132x+11x+1452

x² + 11x - 1452 = 0

x² + 44x - 33x - 1452 = 0

x(x+44) - 33(x+44) = 0

(x+33) (x+44) = 0

x - 44 or x = 33

As the speed cannot be in negative therefore, x = 33 or the speed of the passenger train = 33 km/hr and the speed is 33 + 11 = 44 km/hr

Step-by-step explanation: