Question

Please answer the question in the given attachment

Answer 1

Given

3Tan∅=4

To find

12sin∅-5cos∅/9sin∅-2cos∅

Solution

Here

Tan∅=4/3

Tan∅=p/b

let the value h be k

Then,

from Pythagoras Therom

b²+p²=h²

=>16k²+9k²=h²

=>25k²=h²

=>h=5k

Now coming to the finding t ratios

12sin∅= 12 × 4k/5k

=48/5

5cos∅ = 5 × 3k/5k

=3

9sin∅ = 36/5

2cos∅. = 6/5

Putting the values

12sin∅-5cos∅/9sin∅-2cos∅

$\sf\huge\implies\frac{\frac{48}{5}-3}{\frac{36}{5}-\frac{6}{5}}$

$\implies\frac{3}{2}$