Question

please answer the question in the photo attached! pls give correct answer and don't answer any rubbish pls ​

Answer 1

Step-by-step explanation:

in the above figure ABCD is a cyclic quadrilateral

so angles B and D are add up-to 180

so angle ABC+angle CDA=180

angle ABC=180-70=110

if O is the center then AD will be diameter and angle in the semi circle will be 90

so angle AED =90

and angle EAD=60 (given)

so angle ADE=180-90-60= 30

3)

angle BCD =90+ angle BCA

so angle BCA= 180-angle BAC -angle ABC

so angle BCA=180-110-30= 40

so angle BCD= 90+40= 130