Question

Please answer the question...
It's important​

Answer 1

Explanation:

object distance (u)=-10

focal length ( f)=5

image distance(v)=?

1/f=1/v+1/u

1/5=1/v+1/-10

1/5+1/10=1/v

(2+1)/10=1/v

3/10=1/v

v=10/3

v=3.333..

if v is positive than the image is virtual and erect

upright.

the image distance = 3.3334cm